ISO2531 En545 En598 Ductile Iron Pipe Ductile Iron Fitting Iron Pipe for Wholesale

DUCTILE IRON PIPE EN545/ EN598/ ISO2531   MaterialDuctile Iron 420-10 (DN60-DN2000), Ductile Iron 420-7Length5.5 m to 6 mSpecificationK7, K8, K9-K12 & C20, C25, C30, C40-C100ApplicationPotable Water / Drinking WaterSewage WaterConnection JointT Type / K Type / Anchoring Joint / Self-Restrained JointExternal CoatingZinc + Bitumen/Epoxy Painting / ZnAl (85% + 15%) + Bitumen/Epoxy Painting / Polyurethane Coating (as per ISO8179), with Polyethylene Sleeve as per ISO8180Internal LiningOrdinary Portland Cement / Sulphate Resistance Cement / High-Alumina CementMortar Lining, Polyurethane Coating (as per ISO4179)StandardISO 2531, EN545, EN598 and other major standards.Quality ControlMechanical Properties TestingChemical Component Analysis Hydraulic pressure Test Rubber GasketEPDM / SBR / NBR (EN681-1, ISO4633)CertificationBSI, SGS, BV, TUV, WRAS ......FAQ1.Q: Are you manufacture or trade company?A: We are a manufacturer factory and we also have our own exporting license.2.Q: Can I get free samples?A: Yes, we can provide you the free samples, but you need to bear their own delivery costs. 3.Q: Can I have my own Logo on the product?A: Yes, you can send us your drawing and we can make your logo, but you have to bear their own the cost.4.Q: Can you produce the products according to my own drawings?A: Yes, we can produce the products according to your drawings that will be most satisfy you.5.Q: Can I request to change the form of packaging and transportation?A: Sure, we're glad to fulfill your requirement. Yet please understand that extra costs may occur if the form of packaging and transportation are changed.6.Q: Why trust in us ?AMore than 20 years in this industry . It makes us professional .Good credit in this market. All of our machines are the assurance of our responsibility.    7. More questions please feel free to contact us./* March 10, 2023 17:59:20 */!function(){function s(e,r){var a,o={};try{e&&e.split(",").forEach(function(e,t){e&&(a=e.match(/(.*?):(.*)$/))&&1